3884000=1x^2+2x+1

Solution for 3884000=1x^2+2x+1 equation:

3884000=1x^2+2x+1

We move all terms to the left:

3884000-(1x^2+2x+1)=0

We get rid of parentheses

-1x^2-2x-1+3884000=0

We add all the numbers together, and all the variables

-1x^2-2x+3883999=0

a = -1; b = -2; c = +3883999;
Δ = b2-4ac
Δ = -22-4·(-1)·3883999
Δ = 15536000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15536000}=\sqrt{1600*9710}=\sqrt{1600}*\sqrt{9710}=40\sqrt{9710}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-40\sqrt{9710}}{2*-1}=\frac{2-40\sqrt{9710}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+40\sqrt{9710}}{2*-1}=\frac{2+40\sqrt{9710}}{-2}
$